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position within same nodes
- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: [xsl] position within same nodes
- From: Laurence O Garfield <lgarfiel at students dot depaul dot edu>
- Date: Thu, 19 Jul 2001 13:35:10 -0500 (CDT)
- Reply-To: xsl-list at lists dot mulberrytech dot com
What is the XPath to get the position of a given node relative to its
siblings of the same name? Eg,
<blah>
<argh/>
<meep/>
<meep/>
<stuff/>
<meep/>
</blah>
I'm looking for an XPath statement that would return 1 for the first meep,
2 for the second, and 3 for the 3rd meep, rather than 2, 3, and 5 (which
is what plain position() returns).
I'm trying to count the number of siblings and subtract the number of
siblings of the same type, then subtract that from position(), but I can't
get either of the first two parts there to work either. Does anyone have
any suggestions?
--Larry Garfield
lgarfiel@students.depaul.edu
-- "If at first you don't succeed, skydiving isn't for you." :-)
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