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RE: whitespace as a parameter to a template (replace linefeed with linefeed tab)
- To: "'Jeni Tennison'" <mail at jenitennison dot com>
- Subject: RE: [xsl] whitespace as a parameter to a template (replace linefeed with linefeed tab)
- From: "MacEwan, James (Information Services)" <James dot MacEwan at investorsgroup dot com>
- Date: Thu, 31 May 2001 09:35:28 -0500
- Cc: "'xsl-list at lists dot mulberrytech dot com'" <xsl-list at lists dot mulberrytech dot com>
- Reply-To: xsl-list at lists dot mulberrytech dot com
Jeni,
Thanks for the feedback.
> You'll probably find it easiest to just use the select attribute to
> set the parameter values rather than the content of the
> xsl:with-param:
> <xsl:call-template name="do-replace">
> <xsl:with-param name="text" select="$x" />
> <xsl:with-param name="replace" select="' '" />
> <xsl:with-param name="by" select="' 	'" />
> </xsl:call-template>
Your first idea does not work with Saxon. I get "Unexpected token EOF in
expression". (This tells me that the contents of select are getting
converted to the empty string.)
The second idea does work...
<xsl:call-template name="do-replace">
<xsl:with-param name="text" select="$x"/>
<xsl:with-param name="replace"><xsl:text> </xsl:text></xsl:with-param>
<xsl:with-param name="by"><xsl:text> 	</xsl:text></xsl:with-param>
</xsl:call-template>
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