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Re: xml include


yes, the structure you wrote is true ...


----- Original Message -----
From: "Daniel Newman" <daniel.newman@bis-web.net>
To: <xsl-list@lists.mulberrytech.com>
Sent: Wednesday, April 11, 2001 1:22 PM
Subject: RE: [xsl] xml include


> I'd get rid of the // in your select. They're not needed. Are title and
> author first child nodes?
>
> <root>
>   <title />
>   <author />
> </root>
>
> Daniel.
>
> -----Original Message-----
> From: owner-xsl-list@lists.mulberrytech.com
> [mailto:owner-xsl-list@lists.mulberrytech.com]On Behalf Of Zafer Bayraktar
> Sent: 11 April 2001 12:02
> To: xsl-list@lists.mulberrytech.com
> Subject: [xsl] xml include
>
>
> Hi,
>     I have two xml files, one of them is included in other:
>
> <?xml version="1.0"?>
> <document xmlns:xinclude="http://www.w3.org/1999/XML/xinclude">
>   <xinclude:include href="xml.xml"/>
> </document>
>
> And I use this xsl to transform:
> <?xml version="1.0"?>
> <xsl:stylesheet version='1.0'
> xmlns:xsl='http://www.w3.org/1999/XSL/Transform' >
> <xsl:output method="html" />
> <xsl:template match="/">
> <H1><xsl:value-of select="//title"/></H1>
> <H2><xsl:value-of select="//author"/></H2>
> </xsl:template>
> </xsl:stylesheet>
>
> (xml.xml contains title and author tags)
>
> The problem is that xsl cannot read title and author tags ... ?
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


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