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Re: sorting the unique elements
- To: xsl-list at mulberrytech dot com
- Subject: Re: sorting the unique elements
- From: Oliver Becker <obecker at informatik dot hu-berlin dot de>
- Date: Thu, 7 Sep 2000 19:34:33 +0200 (MET DST)
- Reply-To: xsl-list at mulberrytech dot com
Hi David,
> I realise this has been asked a few times now, but after reading all the
> FAQ's there are about XSLT and trying all kinds of codes I give up...
I think you should read this:
http://www.jenitennison.com/xslt/grouping/muenchian.html
> My problem is the following. I have an XML file like this:
>
> <A>
> <D>
> <C/>
> <A><B/></A>
> </D>
> <B/>
> </A>
>
> I would like to generate a sortered output of the unique elements in the XML
> file like this:
>
> ABCD
Applying the described approach (the muenchian method) I get the following
stylesheet:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="elements" match="*" use="name()" />
<xsl:template match="/">
<xsl:for-each select="//*[generate-id() =
generate-id(key('elements',name())[1])]">
<xsl:sort select="name()" />
<xsl:value-of select="name()" />
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Have fun,
Oliver
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