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RE: Grouping by a piece of a date


I had pitched this yesterday in response to Steve's answer, but hadn't
gotten any further input so I thought I might stoke the fire a bit - to
summarize...

From this XML:

<xml xmlns:s="uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882"
   xmlns:dt="uuid:C2F41010-65B3-11d1-A29F-00AA00C14882"
   xmlns:rs="urn:schemas-microsoft-com:rowset" xmlns:z="#RowsetSchema">

   <rs:data>
      <z:row iID="1" dCreated="1900-01-01T01:00:00"/>
      <z:row iID="2" dCreated="1900-01-02T01:00:00"/>
      <z:row iID="3" dCreated="1900-01-02T02:00:00"/>
      <z:row iID="4" dCreated="1900-01-04T01:00:00"/>
   </rs:data>
</xml>

I am trying to group the elements based on only the date part of the
dCreated value - resulting in:
   1900-01-01T01:00:00	- iID1
   1900-01-02T01:00:00	- iID2, iID3
   1900-01-04T01:00:00	- iID4


Steve Muench suggested that the following should net me the unique keys that
I could use the Meuncharian method to process through:
   <xsl:key name="foo"
      match="/xml/rs:data/z:row"
      using="substring-before(@dCreated,'T')"/>

Unfortunately, the following outputs no results (using the MSXML3 July
preview rel).:
   <xsl:for-each
      select="/xml/rs:data/z:row[generate-id(.)=generate-id(key('foo',.))]"
>
         <xsl:value-of select="." />
   </xsl:for-each>

Am I missing something/doing something incorrectly, or could someone
confirm/deny that MSXML3 doesn't currently support this?

Much appreciation in advance - Cheers, 
	  
	  
Jeffrey J. Saylor 
Senior Internet Developer 
Diamond Technology, Inc. 
707 Mendham Blvd., Suite 104 
Orlando, FL 32825 
Phone: (407) 262-9000 Ext 266 
Fax: (407) 262-9010 
Email: jsaylor@DiamondTechnology.com 


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