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Quotes after --args
- From: "Markus Bühren" <bhr2 at gmx dot de>
- To: gdb at sourceware dot org
- Date: Fri, 08 Jun 2012 16:21:02 +0200
- Subject: Quotes after --args
- References: <1339164112.4081.ezmlm@sourceware.org>
Hi,
I am using the GNU gdb 6.8 under Windows. I am trying to run a program that is invoked like
test.exe -f "my testfile.txt"
in batch mode. This is my command line:
gdb --eval-command=run --batch --args test.exe -f "my testfile.txt"
My program should get two arguments, '-f' and 'my testfile.txt'. However, replacing my actual program test.exe by a program that just prints the input arguments, I get the following result:
C:\>gdb --eval-command=run --batch --args test.exe -f "my testfile.txt"
[New thread 6180.0xad0]
argv[0] = >>C:/test.exe<<
argv[1] = >>-f<<
argv[2] = >>my\<<
argv[3] = >>testfile.txt<<
Program exited normally.
Can you help me to avoid that the file name is splitted into two arguments, with replacing the blank ' ' after 'my' by a backslash '\'? I have tried a lot of combinations of double double quotes '""', escaped double quotes '\"' and so on but I did not manage to get the file name passed as a single argument into my program.
Yours
Markus
PS: Renaming the file is not an option - actually, I already simplified matters here to a file name with a blank in it.
PPS: For your reference, this is the C code of my simple program returning the arguments:
#include <stdio.h>
void main(int argc, char *argv[])
{
int k;
for(k = 0; k < argc; k++)
{
printf("argv[%d] = >>%s<<\n", k, argv[k]);
}
}