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Hi, currently "print/x (float) a" does an integer "print/x (long) a". Ulrich Drepper requested to use instead printf ("%a") (man excerpt below): Implemented as: (gdb) print/x $xmm5 $1 = {v4_float = {0x5, 0x5, 0x5, 0x5}, v2_double = {0xc00, 0x1800}, v16_int8 -> (gdb) print/x $xmm5 $1 = {v4_float = {0x1.400000000p+2, 0x1.500000000p+2, 0x1.600000000p+2, 0x1.700000000p+2}, v2_double = { 0x1.8000040a000000000p+11, 0x1.8000040b000000000p+12}, v16_int8 = {0x0, 0x0, 0xa0, 0x40, 0x0, 0x0, With the original value: (gdb) print $xmm5 $1 = {v4_float = {5, 5.25, 5.5, 5.75}, v2_double = {3072.0004930496216, 6144.0009870529175}, v16_int8 = {0 '\0', 0 '\0', -96 '?', 64 '@', 0 '\0', Implementation attached. Systems not supporting "%a" will print the value as print (float) a which differs from the current way there: print/x (long) a Regards, Jan a,A (C99; not in SUSv2) For a conversion, the double argument is converted to hexadecimal notation (using the letters abcdef) in the style [-]0xh.hhhhp±d; for A conversion the prefix 0X, the letters ABCDEF, and the exponent separator P is used. There is one hexadecimal digit before the decimal point, and the number of digits after it is equal to the precision. The default precision suffices for an exact representation of the value if an exact representation in base 2 exists and otherwise is sufficiently large to distinguish values of type double. The digit before the decimal point is unspecified for non-normalized numbers, and non-zero but otherwise unspecified for normalized numbers.
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