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Re: BUG: stdin not a constant


Hi, raf.

In message "Re: BUG: stdin not a constant"
    on 97/12/08, raf <raf@comdyn.com.au> writes:

raf> stdout is probably defined as "(&__iob[1])" which is just an
raf> expression because of the parentheses. #undef it a #define it as
raf> "&__iob[1]" which is a constant.

This solution seems meaningless with three reasons.

(1) When expression a was constant, "(a)" should be still remaining as
constant (expression). If your idea was correct, we may couldn't write
following statement as global variable definition/initilizer.

	int n = (0);

(2) Actual definition of stdout came from Cygnus (b18) is;

	#define	stdout	(_impure_ptr->_stdout)

(3) Your solution (remove parentheses) still causes same error
message.

Why don't you see actual stdio.h file? And, why don't you try -E
option of gcc?

# Forgive me if my expression brings unpleasant feelings to someone.
# Still I couldn't realize tone of English expressions.

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