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Re: ld -e number makes an entry in symbol table
On Wed, Sep 09, 2009 at 08:50:23AM -0700, H.J. Lu wrote:
> On Wed, Sep 9, 2009 at 8:23 AM, Andreas Schwab<schwab@redhat.com> wrote:
> > This was broken by the patch for PR ld/6766.
>
> Here is a patch. OK to install?
I obviously gave the OK for your PR6766 patch too quickly. I'm
inclined to think the whole patch should be reverted.
Why should -e be any different from ENTRY() in a script?
--
Alan Modra
Australia Development Lab, IBM